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Criteria is still a pure Hibernate Core API and requires a Session object to be built. You can access the Session object underneath a Hibernate EntityManager instance by using the getDelegate() method: Session session = (Session) entityManager.getDelegate();. When Java Persistence supports a Criteria-like API, Hiber-

page number, or a pointer, which directs you to where you can find the data you re looking for. This is where an index within your SQL Server database comes in. You define an index in SQL Server so that it can locate the rows it requires to satisfy database queries faster. If an index does not exist to help find the necessary rows, SQL Server has no other option but to look at every row in a table to see if it contains the information required by the query. This is called a table scan, which by its very nature adds considerable overhead to data-retrieval operations.

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Use the AdventureWorks2008 database to complete this exercise. 1. Write a query using the Sales.SpecialOffer table. Display the difference between the MinQty and MaxQty columns along with the SpecialOfferID and Description columns. SELECT SpecialOfferID, Description, MaxQty - MinQty AS Diff FROM Sales.SpecialOffer; 2. Write a query using the Sales.SpecialOffer table. Multiply the MinQty column by the DiscountPct column. Include the SpecialOfferID and Description columns in the results. SELECT SpecialOfferID, Description, MinQty * DiscountPct AS Discount FROM Sales.SpecialOffer; 3. Write a query using the Sales.SpecialOffer table that multiplies the MaxQty column by the DiscountPCT column. If the MaxQty value is null, replace it with the value 10. Include the SpecialOfferID and Description columns in the results. SELECT SpecialOfferID, Description, ISNULL(MaxQty,10) * DiscountPct AS Discount FROM Sales.SpecialOffer; 4. Describe the difference between division and modulo. When performing division, you divide two numbers, and the result, the quotient, is the answer. If you are using modulo, you divide two numbers, but the reminder is the answer. If the numbers are evenly divisible, the answer will be zero.

the full-text query targeted entity. Hibernate Search raises an exception otherwise. Some people are tempted to use additional restrictions on the Criteria query injected into a Hibernate Search query. After all, it would mean restricting the query further by some additional SQL clauses on top of the Lucene restrictions. This approach has two major problems: Pagination is no longer respected, and the total number of results is incorrect. Pagination is applied to the Lucene query before loading any object and does not take into account that objects will be filtered out by the Criteria/SQL restriction. After pagination is applied, if an object cannot be loaded for a given document (because it cannot be found by the loading query), it is ignored and not returned in the results. The list of results seen through pagination is like a gigantic piece of Gruyere: It has lots of holes, making it practically unusable. Likewise, the total number of results is built from the total number of matching Lucene documents and cannot account for the SQL-based filtering. Some Lucene results will puzzle you. Fortunately, there are ways to understand what s going on.

There will be times when a table scan is the preferred option over an index. For example, if SQL Server needs to process a reasonable proportion of rows within a table, sometimes estimated to be around 10 percent or more of the data, then it may find that using a table scan is better than using an index. This is all to say that a table scan isn t wholly a bad thing, but on large tables, it could take some time to process.

B The bridge transforms price into a padded number rounded to the next integer. C The maximum price is passed to the filter as a parameter. D RangeFilter has a

Use the AdventureWorks2008 database to complete this exercise. Be sure to refer to the discussion of the functions to help you figure out which ones to use if you need help. 1. Write a query that displays the first 10 characters of the AddressLine1 column in the Person.Address table. Here are two possible solutions: SELECT LEFT(AddressLine1,10) AS Address10 FROM Person.Address; SELECT SUBSTRING(AddressLine1,1,10) AS Address10 FROM Person.Address;

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